mysql的隐式的数据类型转换_自学php网
来源:自学PHP网
时间:2014-12-04 22:12 作者:
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[导读] mysql select * from orders;+----+---------------------------+| id | order_id |+----+---------------------------+| 1 | 0300020140124034500255929 || 2 | 0300020140124034500268504 || 3 | 0300020140124034500648644 || 4 | 0300020140124034500268XX...
mysql> select * from orders;
+----+---------------------------+
| id | order_id |
+----+---------------------------+
| 1 | 0300020140124034500255929 |
| 2 | 0300020140124034500268504 |
| 3 | 0300020140124034500648644 |
| 4 | 0300020140124034500268XXX |
| 5 | 0300020140124034500200000 |
| 6 | 0300020140124034500800000 |
+----+---------------------------+
6 rows in set (0.00 sec)
mysql> select * from orders where order_id=0300020140124034500255929;
+----+---------------------------+
| id | order_id |
+----+---------------------------+
| 1 | 0300020140124034500255929 |
| 2 | 0300020140124034500268504 |
| 3 | 0300020140124034500648644 |
| 5 | 0300020140124034500200000 |
| 6 | 0300020140124034500800000 |
+----+---------------------------+
5 rows in set, 1 warning (0.00 sec)
先看order表数据,order_id是varchar类型,执行select的查询条件没有加单引号,这时候查询出来6条结果,为什么会出来这么多结果,按上面的写法mysql会把上面的条件order_id=0300020140124034500255929看做数字,但是看做什么数字不是很清楚
mysql> show warnings;
+---------+------+---------------------------------------------------------------+
| Level | Code | Message |
+---------+------+---------------------------------------------------------------+
| Warning | 1292 | Truncated incorrect DOUBLE value: '0300020140124034500268XXX' |
+---------+------+---------------------------------------------------------------+
1 row in set (0.00 sec)
mysql> select * from doubles;
+----+----------------------+
| id | order_id |
+----+----------------------+
| 1 | 3.000201401240345e23 |
| 2 | 3.000201401240345e23 |
| 3 | 3.000201401240345e23 |
+----+----------------------+
从warning上来看是转为double了,把order_id的类型变为double发现存储的结果都变为科学计数法了,这样就找到原因了,经过mysql隐式转换的结果会有精度丢失,造成了上面的查询不准确
所以建议大家不要借助 MySQL 的隐式转换,程序严格按数据的本来类型来处理,会少很多不必要的麻烦。 |
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