来源:自学PHP网 时间:2015-04-16 23:15 作者: 阅读:次
[导读] Function fnUploadImg(ByVal upFile As HttpPostedFile, ByVal uploadPath As String) As String Dim result As String = Dim intImgSize As Int32 intImgSize = upFile Conten...
Function fnUploadImg(ByVal upFile As HttpPostedFile, ByVal uploadPath As String) As String Dim result As String = "" Dim intImgSize As Int32 intImgSize = upFile.ContentLength If intImgSize <> 0 Then If intImgSize > 500000 Then result = "图片太大" Return result Exit Function End If Dim strImgType As String = upFile.ContentType '只接受.jpg格式的图片 Dim filesplit() As String = Split(strImgType, "/") strImgType = filesplit(filesplit.Length - 1) If strImgType = "jpg" Or strImgType = "jpeg" Then Else result = "图片格式错误" Return result Exit Function End If filesplit = Split(upFile.FileName, "\") Dim filename As String = filesplit(filesplit.Length - 1) upFile.SaveAs(Server.MapPath("upload\location\" & uploadPath) & "\" & filename) Dim imgpath As String = "upload/location/" & uploadPath & "/" & filename result = imgpath Return result End If End Function 突破方法:上传任意文件,抓包修改Content-Type为:image/jpeg |
自学PHP网专注网站建设学习,PHP程序学习,平面设计学习,以及操作系统学习
京ICP备14009008号-1@版权所有www.zixuephp.com
网站声明:本站所有视频,教程都由网友上传,站长收集和分享给大家学习使用,如由牵扯版权问题请联系站长邮箱904561283@qq.com